Question

Find the area of the regular trapezoid below​

Answer 1

Check the picture below.

`\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{parallel~sides}{bases}\\ h=height\\[-0.5em] \hrulefill\\ h=6\\ a=6\\ b=12 \end{cases} \\\\\\ A=\cfrac{6(6+12)}{2}\implies A=3(18)\implies A=54`

Answer 2

54in.

Explanation:

A= b+b/2*h

12+6= 18

18/2= 9

9*6= 54