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If we desired to estimate the average mechanical aptitude of a large population of workers, how large a random sample would we need to be able to assert with a probability of 0.95 that the sample mean will be within 2 points of the population (true) mean? Assuming that it is known from past experience with similar data that σ = 16.

User Monkut
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1 Answer

5 votes

Answer: 246

Explanation:

As per given description , we have

Population standard deviation:
\sigma=16

Critical value for 95% confidence =
z_(\alpha/2)=1.96

margin of error : E= 2

Formula to find the required sample size : -


n=((z_(\alpha/2)\sigma)/(E))^2\\\\=((1.96*16)/(2))^2\\\\=245.8624\approx246

Hence, the required minimum sample =246

User Eddie Kumar
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