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The temperature of a plastic cube is monitored while the cube is pushed 1.8 m across a floor at constant speed by a horizontal force of 24 N. The monitoring reveals that the thermal energy of the cube increases by 18 J. What is the increase in the thermal energy of the floor along which the cube slides?

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Answer: 25.2 Joules

Step-by-step explanation:

Work = total heat energy = Fs = (24)(1.8) = 43.2 J

Heat = cube + floor = 43.2J

floor = 43.2 J - 18 J = 25.2 J

User Guillermo Garza
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