Question

If the voltage across a circuit of constant resistance is doubled, how is the current in the circuit affected?

(a)-The current is quadrupled.
(b)-The current is reduced by a factor of 2.
(c)-The current is reduced by a factor of 4.
(d)-The current remains constant.
(e)-The current is doubled.

Answer 1

(e)-The current is doubled.

Step-by-step explanation:

According to Ohm law,
`I = (V)/(R)` where I is the current, V is the voltage and R is the resistant.

`I_1 = (V_1)/(R_1)`

`I_2 = (V_2)/(R_2)`

If V is doubled,
`V_2 = 2V_1` while R remains constant
`R_2 = R_1` we would have

`I_2 = (2V_1)/(R_1) = 2((V_1)/(R_1)) = 2I_1`

The current is doubled.