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The area of the sandbox is 56 2/3 square feet. The width is 8 1/2 feet. What is the length? Hint: Divide area by length

User BaDr Amer
by
6.6k points

1 Answer

5 votes

Answer:

20/3 ft or 6 2/3 ft

Explanation:

A = 56 2/3 sq ft

W = 8 1/2 ft

L = ?

A = LW

L = A/W


L = (A)/(W)


L = (56~(2)/(3)~sq~ft)/(8~(1)/(2)~ft)

Change the mixed numbers into fractions.


a(b)/(c) = (ac + b)/(c)


L = ((56 * 3 + 2)/(3))/((8 * 2 + 1)/(2))


L = ((170)/(3))/((17)/(2))


L = (170)/(3) / (17)/(2)


L = (170)/(3) * (2)/(17)


L = (170 * 2)/(3 * 17)


L = (17 * 10 * 2)/(3 * 17)


L = (10 * 2)/(3)


L = (20)/(3)

Answer: 20/3 ft or 6 2/3 ft

User Makaron
by
7.1k points
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