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Derivative of (x^7+2x-3)^3

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8 votes

Answer:


\displaystyle (dy)/(dx) = 3(7x^6 + 2)(x^7 + 2x - 3)^2

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:
\displaystyle (d)/(dx)[f(x) + g(x)] = (d)/(dx)[f(x)] + (d)/(dx)[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

Step 1: Define

Identify


\displaystyle y = (x^7 + 2x - 3)^3

Step 2: Differentiate

  1. Basic Power Rule [Derivative Rule - Chain Rule]:
    \displaystyle y' = 3(x^7 + 2x - 3)^2(x^7 + 2x - 3)'
  2. Basic Power Rule [Derivative Properties]:
    \displaystyle y' = 3(7x^6 + 2)(x^7 + 2x - 3)^2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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