Question

(a³-64)÷(a-4)
dividing polynomials
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Answer 1

`\textbf{$a^2 + 4a + 16$}\\`

Explanation:

`\textup{Given:}\\$$ (a^3 - 64)/(a - 4) $$\\\textup{This can be written as:}\\$ (a - 4)(a^2 + 4a + 16) $ \hspace{25mm} $[ (a^3 - b^3) = (a - b)(a^2 + ab + b^2)]$\\`

`\textup{Here $b = 4$}\\\textup{Now, it can be written as}\\$$ ((a - 4)(a^2 + 4a + 16))/(a - 4) $$\\\textup{which renders us}\\`

`$$a^2 + 4a + 16$$`