Question

Design a full-wave bridge rectifier to supply 12V DC voltage to a resistive load of RL=3Ω at the output, assuming an AC supply with 60 Hz frequency with the following characteristics: a) Unfiltered (without output capacitor) b) Filtered. Design a filter capacitor so that the ripple factor of the output voltage is less than %5. (You should revise the AC supply Vm calculated in (a) to match the 12V requirement.)

Answer 1

`V_m= 18.85V` and c= 1.336mF

Step-by-step explanation:

a) Unfiltered

We calculate the Voltage through the equation:

`V_0=(2V_m)/(\pi)\\12=(2V_m)/(\pi)\\V_m= 6\pi V\\V_m= 18.85V`

So,

`V_(in) = 18.85 sin wt\\ w=377Rad/s`

b) Filtered

We need to use the ripple factor,

`rf=\frac{1}{4/sqrt{3}fRc}`

Solving and clearing for c,

`c=(1)/(4√(3)fR*0.6)=1.336mF`

*Note that was given 5% of output voltage