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Determine K such that 2/3, k, 5/8,K are consecutive terms of an ap​

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Answer:

k = 16/33

Explanation:

Determine k so that 2/3,k and 5/8k are the three consecutive terms of an a.p

k - 2/3 = 5/8k - k

3k-2/3 = 5k-8k/8

Cross product

(3k-2)(8) = (3)(5k-8k)

24k - 16 = 15k - 24k

24k - 16 = -9k

24k + 9k = 16

33k = 16

k = 16/33

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