128k views
4 votes
If the cylinder has a diameter of 8 cm and a volume of approximately 502.65 cm3, what is the approximate area of the cross-section shown?

A) 40 cm2
B) 60 cm2
C) 80 cm2
D) 100 cm2

User Ryeager
by
7.4k points

2 Answers

0 votes
It would be 80 because
User JonathanC
by
8.8k points
5 votes

Answer:

80 square centimeters.

The volume of a cylinder is defined as:
V=A.h

Where
A is the area of the base, which is circular:
A= \pi r^(2)

If the diameter is
8cm, then the radius is
4cm, because the radius is defines as one half of the diameter. So, area of the base would be:


A= \pi (4cm)^(2)=16 \pi cm^(2)

Now, we can calculate the height by replacing all given values in the first equation:


502.65=16 \pi h\\h=(502.65)/(16 \pi) \\h \approx 10 cm

So, we assume that the cross section that's being asked is the rectangular one. The base of the rectangle is the diameter of the as circle 8cm, and the height of the rectangle is the height of the cylinder 10cm.

Therefore, the area of the cross section would be:


A_(cross)=(8cm)(10cm)=80cm^(2)

User Tatsuya Fujisaki
by
7.5k points