Answer: B. .131
Explanation:
Given : The proportion of college freshmen support increased spending on environmental issues : p= 0.53
Let x be the binomial variable that represents the number of college freshmen support increased spending on environmental issues.
with parameter p = 0.25 n= 6
Using binomial , we have
![P(x)=^nC_xp^x(1-p)^(n-x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/go5usnnxzkib641nm6qufyixf9qjuc62cs.png)
Required probability :-
![P(x=3)=^6C_3 (0.25)^3(0.75)^3\\\\=(6!)/(3!3!)(0.25)^3(0.75)^3\\\\=0.1318359375\approx0.1318](https://img.qammunity.org/2020/formulas/mathematics/college/c2myv91pnmm20vbjfj5x4ylmlyfjtl63jn.png)
Hence, the probability that exactly 3 support increased spending on environmental issues=0.1318