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J -6 = 1\2 j +3
How do you do it



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4 votes

Answer:


j - 6 = (1)/(2) j + 3 \\ collect \: like \: terms \\ j - (1)/(2) j = 3 + 6 \\ j - (j)/(2) = 9 \\ find \: lcm \\ (2j - j)/(2) = 9 \\ multiply \: both \: side \: by \: 2 \\ (2j - j)/(2) * 2 = 9 * 2 \\ 2 \: cancel \: 2 \\ 2j - j = 18 \\ j = 18

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