Question

X squared +14 X +48 what are the zeros of the function

Answer 1

The zeros of the function X squared +14 X +48 is -6 and -8

Solution:

Need to find zeros of x squared +14x +48 that means needs to find solution of following quadratic equation

`x^(2)+14 x+48=0`

On splitting the middle term so that summation of two terms comes 14x and product of two terms be
`48x^2` , we get

`\begin{array}{l}{x^(2)+8 x+6 x+48=0} \\\\ {=>x(x+8)+6(x+8)=0} \\\\ {=>(x+6)(x+8)=0}\end{array}`

So either x+6 = 0 or x + 8 = 0

when x+6 = 0, x = -6

when x+8 = 0, x = -8

Hence required zeros of
`x^2` + 14x + 48 are -6 and -8.

Answer 2

on x= -6

x=-8

this is the answer