Answer:
Explanation:
No of trials = 290
no of heads =160
Sample proportion p =
![(160)/(290) =0.552](https://img.qammunity.org/2020/formulas/mathematics/college/5u3utfumfkwbt80juor3wtz4qhhuycez4m.png)
![H_0: p=0.5\\H_a: p \\eq 0.5](https://img.qammunity.org/2020/formulas/mathematics/college/aaffrhxji5gnc2fzpneeo7i8fk4uoq3td7.png)
(Two tailed test)
p difference =
![0.552-0.5=0.052](https://img.qammunity.org/2020/formulas/mathematics/college/ii3hsset5spweyqmo9zflh6joofwg8axc2.png)
Std error =
![\sqrt{(0.5(0.5))/(290) } \\=0.02936](https://img.qammunity.org/2020/formulas/mathematics/college/6ehkx279kc8mi62hyuamhxswbn8nvznf8x.png)
Z statistic = 1.77
p value = 0.076
p value >0.05 hence accept that prob for heads is 0.5
If it is 1%p>0.01 hence accept null hypothesis again