83.9k views
22 votes
HELP PLS !!!!!!!!!!!!!!!!!!!!]

A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)

User Makan
by
7.8k points

1 Answer

1 vote

Answer:

0.25

Step-by-step explanation:

According to newtons law of motion

\sum F_x = ma

F_f = ma

nR = ma

nmg = ma

ng = a

n = a/g

g is the acceleration due to gravity

Given

a = 2.42m/s²

g = 9.8m/s²

Substitute into the formula;

n = 2.42/9.8

n = 0.25

Hence the coefficient of kinetic friction is 0.25

User Tyler Marien
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.