Answer:
2
Step-by-step explanation:
So for solving this problem we need the local heat transfer coefficient at distance x,
![h_x=cx^(-1/2)](https://img.qammunity.org/2020/formulas/engineering/college/rzfcintl7q0wh0542ew9m23y8ur40nz39l.png)
We integrate between 0 to x for obtain the value of the coefficient, so
![\bar{h}_x =(1)/(x) \int\limit^x_0 h_x dx\\\bar{h}_x = (c)/(x) \int\limit^x_0 (1)/(√(x))dx\\\bar{h}_x = (c)/(c) (2x^(1/2))\\\bar{h}_x = 2cx^(-1/2)](https://img.qammunity.org/2020/formulas/engineering/college/11fo8xhiacu7u7pbsvrtssidwvsk5mzdny.png)
Substituing
![\bar{h}_x=2h_x\\\frac{\bar{h}_x}{h_X}=2](https://img.qammunity.org/2020/formulas/engineering/college/94mri6z6net02l1uoiahpks88663gu7z2g.png)
The ratio of the average convection heat transfer coefficient over the entire length is 2