Question

James (mass 93.0 kg ) and Ramon (mass 55.0 kg ) are 20.0 m apart on a frozen pond. Midway between them is a mug of their favorite beverage. They pull on the ends of a light rope stretched between them. Ramon pulls on the rope to give himself a speed of 1.10 m/s. What is James's speed?

Answer 1

Velocity of james will be 0.6505 m/sec

Step-by-step explanation:

We have given mass of James
`m_1=93 kg`

Mass of Ramon
`m_2=55 kg`

Velocity of Roman
`v_2=1.1m/sec`

Initial both are at rest so initial momentum = 0

From conservation of momentum we know that

Initial momentum = final momentum

So
`m_1v_1+m_2v_2=0`

`93* v_1+55* 1.1=0`

`v_1=-0.6505m/sec`

Negative sign shows the direction of velocity

Answer 2

v₁ = - 0.65 m/s (opposite to the direction of Ramon)

Step-by-step explanation:

Given that

m ₁= 93 kg (James )

m₂ = 55 kg ( Ramon)

v₂=1.1 m/s

The velocity of James = v₁

There is no any external force so linear momentum will remain conserve

0 = m ₁ v₁ + m₂ v₂

m ₁ v₁ = - m₂ v₂

93 v₁ = - 55 x 1.1

v₁ = - 0.65 m/s (opposite to the direction of Ramon)