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The corners of a triangle garden are marked with trees at coordinates (0,3),(3,0), and (4,3). Let a denote the area of the garden, in square units. Which of the following is true?

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Given:

Three corner points of a triangular garden are (0,3),(3,0), and (4,3).

To find:

The area of the garden.

Solution:

We know that, area of a triangle is


A=(1)/(2)|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

Let a denote the area of the garden, in square units.

Three vertices of the triangular garden are (0,3),(3,0), and (4,3). So, area of the triangular garden is


a=(1)/(2)|0(0-3)+3(3-3)+4(3-0)|


a=(1)/(2)|0(-3)+3(0)+4(3)|


a=(1)/(2)|0+0+12|


a=(1)/(2)* 12


a=6

Therefore, the area of the garden is a=6 square units.

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