169k views
4 votes
With what speed must an object be thrown to reach a height of 400m. Assume negligible air resistance.

1 Answer

6 votes

Final velocity(v)² - Initial Velocity(u)² = 2 * acceleration due to gravity(g) * height(h)

While the object will attain its maximum height the final velocity will be 0 m/s

0² - u² = 2 * -9.8 * 91.5

-u² = -1793.4

u² = 1793.4

u = √1793.4

u = 42.35(appx)m/s

=42.35 * 2.23 mi/s

=94.44 mi/s(appx)

if you need more help and you dont understand talk to your teacher or look it up on quizlet.

User Pduey
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.