Question

a 20 of of ice at 0c is dropped into water at boiling point, specific heat capacity of water =4200 J/kg•c, sepesific latent heat of fusion (Lf) =3.3x10^(5) J/kg calculate the amount of heat energy needed to complete the previous conversion​

Answer 1

15 KJ

Step-by-step explanation:

The quantity of heat (Q) required is given as:

Q = mcΔθ + mL

where m is the mass of ice, c is its specific heat capacity, L is its specific latent heat andΔθ is the change in temperature.

Given: m = 20g, temperature of ice = 0
`^(o) C`, specific heat capacity of water = 4200 J/kg
`^(o) C`, latent heat of fusion of ice = 3.3 x 10^(5) J/kg, temperature of water = 100
`^(o) C`.

Q = m (cΔθ + L)

= 0.02(4200 x (100) + 330000)

= 0.02(420000 + 330000)

= 0.02 (750000)

Q = 15000

Q = 15000 Joules

Q = 15KJ

The quantity of heat needed to complete the conversion is 15 KJ.