Question

What is an equation of the line that passes through the point (−6,−1) and is perpendicular to the line 6x−y=7?

Answer 1

y=-1/6x-2

Explanation:

Lets find the slope of the given line

6x-7=y,m=6

The slope of the perpendicular line would be=-1/6

Using the point-slope form y-y1=m(x-x1)

y--1=-1/6(x--6)

y+1=-1/6(x+6)

6y+6=-x-6

6y=-x-6-6

6y=-x-12

y=-1/6x-2