Question

14. There were 200 tickets sold for a women's basketball game. Tickets for students were 50 cents each

and for adults 75 cents each. The total amount of money collected was $132.50. How many of each type
of ticket was sold?

Answer 1

Number of students ticket sold = 70

Number of Adult ticket sold = 130

Explanation:

Given as ,

Total number of tickets sold = 200

Each student tickets cost = 50 cents = $0.5 Note : $ 1 = 100 cents

Each Adult tickets cost = 75 cents = $0.75

Total amount of money collected = $ 132.50

Now,

Let student = S and Adult = A

So, S + A = 200 .... 1

And, 0.5S + 0.75 A = 132.50 ....2

Solve both equations

0.5 S + 0.5 A = 100

0.5 s + 0.75 A = 132.52

Again, (0.5 S + 0.75 A) - (0.5 S + 0.5 A ) = 32.50

0.25 A = 32.50

so , A = 130

Now put this A value in above eq ,

Then, 0.5S + 0.5 (130) = 100

0.5 S = 100 - 65 = 35

So , S =
`(35)/(0.5)` = 70

Hence, Number of students ticket sold = 70

Number of Adult ticket sold = 130 Answer