Question

Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation

C6H12O6 (aq) + 6O2 (g) = 6CO2 (g) + 6H2O (l)
Calculate the number of grams of oxygen required to convert 63.0 g of glucose to CO2 and H2O.
_____________________g O2
Also compute the number of grams of CO2 produced.
_____________________g CO2

Answer 1

We need 67.2 grams of 02. There will be produced 92.421 grams of CO2

Step-by-step explanation:

Step 1: The balanced equation

C6H12O6 (aq) + 6O2 (g) = 6CO2 (g) + 6H2O (l)

Step 2: Data given

We can see that for 1 mole C6H12O6 consumed, we need 6 moles of O2 to produce 6 moles of CO2 and 6 moles of H2O

The mass of glucose is 63.0g

The molar mass of glucose is 180.156 g/mole

The molar mass of O2 is 32 g/mole

The molar mass of CO2 is 44.01 g/mole

Step 3: Calculate number of moles of glucose

Number of moles of glucose = mass of glucose / molar mass of glucose

Number of moles of glucose = 63 grams /180.156 g/moles = 0.35 moles

Step 4: Calculate number of moles of oxygen ( and CO2)

For 1 mole of glucose we need 6 moles of O2 to produce 6 moles of CO2 and 6 moles of H2O

So for 0.35 moles of glucose we need 6*0.35 = 2.1 moles of O2 to produce 2.1 moles of CO2 and 2.1 moles of H2O

Step 5: Calculate mass of oxygen ( and CO2)

mass of oxygen = number of moles of oxygen * Molar mass of oxygen

mass of oxygen = 2.1 moles * 32 g/mole = 67.2 g O2 (≈ 67 grams)

mass of CO2 = number of moles of CO2 * Molar mass of CO2

mass of CO2 = 2.1 moles * 44.01 g/mole = 92.421 grams

We need 67.2 grams of 02. There will be produced 92.421 grams of CO2