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Can someone please do this quick

Can someone please do this quick-example-1
User Bastiaan
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1 Answer

4 votes

Answer:

1) a = 3.2 m/s²

2) d = 160 m

3) d = 30 m

Step-by-step explanation:

1) Given,

The initial velocity of the car, u = 0

The final velocity of the car, v = 32 m/s

The time taken to complete the trip is, t = 10 s

The acceleration of the car is,

a = (v - u) / t

= (32 - 0) / 10

= 3.2 m/s²

The constant acceleration of the car is, a = 3.2 m/s²

2) The total distance covered by the car is given by

d = vₐ x t

= 16 x 10 ∵ Average velocity = (32 - 0)/2

= 160 m

Hence, the total distance covered by the car is, d = 160 m

3) Given,

The initial velocity of the jogger, u = 0

The final velocity of the jogger, v = 6 m/s

The time taken by the jogger to reach the final velocity is, t = 10 s

The distance covered by the jogger,

d = vₐ x t

= 3 x 10 ∵ vₐ is the average velocity

= 30 m

Hence, the distance covered by the jogger is, d = 30 m

User Otake
by
5.6k points