Question

A 6.0-kg object undergoes an acceleration of 2.0 m/s2. (a) What is the magnitude of the resultant force act- ing on it? (b) If this same force is applied to a 4.0-kg object, what acceleration is produced?

Answer 1

a) 12 N

b) 3 m/s²

Step-by-step explanation:

m = Mass of the object

a = Acceleration of the object

Force

`F=ma\\\Rightarrow F=6* 2\\\Rightarrow F=12\ N`

Now, F = 12 N

The resultant force acting on the object is 12 Newtons

`a=(F)/(m)\\\Rightarrow a=(12)/(4)\\\Rightarrow a=3\ m/s^2`

The acceleration of the 4 kg object which is experiencing the same force is 3 m/s²