Question

Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction.

x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
x = StartFraction negative 6 plus or minus StartRoot (negative 6) squared minus 4 (9)(1) EndRoot Over 2(9) EndFraction
x = StartFraction negative 6 plus or minus StartRoot 36 minus 36 EndRoot Over 18 EndFraction
x =

Answer 1

x = -1/3

Explanation:

x = [-6 +- squareRoot(36-4x9)] / 2 times (-6)

= -6/18 = -1/3

x-(-1/3) = 0 ---> x = -1/3

Answer 2

`x=\frac{-6\pm \sqrt{6^(2)-4(9)(1)}}{2*9}`

Explanation:

For this function [f(x)=9x²+6x+1], we'll solve it by the traditional way, via General Formula

`9x^(2)+6x+1=0 \Rightarrow x=\frac{-6\pm \sqrt{6^(2)-4(9)(1)}}{2*9}\Rightarrow x=-(1)/(3)\Rightarrow S=\left \{ -(1)/(3) \right \}`