Question

A section of a genome is cut with three enzymes: A, B, and C. Cutting with A and B yields a 10-kb fragment. Cutting with B and C yields a 2-kb fragment. What is the expected result from a digest with A and C, if the C site lies in between the A and B sites?

Answer 1

8-kb

Step-by-step explanation:

As you can see in the picture attached, the cutting sites are consecutively situated in the genome. For that reason, if the largest fragment results when A and B cut, and the cutting site of C is betwen A and B, then the fragment expected from a digest with A and C could be calculated as follows:

`AC=AB-BC =10 kb- 2kb=8kb`