Answer:
a) Outcomes making up event A are (1,2,3,4+)
P(A) = 0.48
b) Outcomes making up event B are (0,1,2)
P(B) = 0.89
c) Outcomes making up event C are (0,1,2,3,4+)
P(A or B) = 1
Explanation:
a) P(A) = P(X = 1)+P(X = 2)+P(X = 3)+P(X = 4+)
= 0.28+0.09+0.04+0.07= 0.48
b) P(B) = P(X = 0)+P(X = 1)+P(X = 2)
= 0.52+0.28+0.09 = 0.89
c) A and B are non-mutually exclusive, they can both occur at the same time.
Thus, the probability that A or B will occur is given by:
P(A or B) = P(A) + P(B) - P(A∩B)
But P(A∩B)= P(X=1) + P(X=2)= 0.28+0.09=0.37
Hence, P(A or B) = 0.48+0.89-0.37 = 1
P(A or B) in not equal to P(A) + P(B) because events A and B are not mutually exclusive.