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A pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0-kg sphere suspended from a 67.0-m light cable. How long would it take for the bob in this pendulum to move from the position of maximum displacement down to the equilibrium point?

User Ozymandias
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1 Answer

5 votes

Answer:

4.11 s.

Step-by-step explanation:

The period T of oscillation of the pendulum is given by the formula:


T = 2 \pi * \sqrt{(L)/(g) }

The maximum oscillation point it can reach is 45 °,

This point is the equivalent of T / 4, which is the moment when it reaches equilibrium.

So for T / 4,


T = 2\pi * √(l / g) = 2 \pi √((67 / 9.81)) = 16.42


t = T / 4 = 16.42 / 4 = 4.11 s

User Newton Joshua
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