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Ralph and Melissa watch lots of videos. But they have noticed that they don't agree very often. In fact, Ralph only likes about 10% of the movies that Melissa likes, i.e., P(Ralph likes a movie|Melissa likes the movie) = .10 They both like about 37% of the movies that they watch. (That is, Ralph likes 37% of the movies he watches, and Melissa likes 37% of the movies she watches.) If they randomly select a movie from a video store, what is the probability that they both will like it? prob. =

User Phan
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Answer:

There is a 3.7% probability that they both will like it.

Explanation:

We can solve this problem using the Bayes rule derivation from conditional probability.

Bayes rule:

What is the probability of B, given that A?


P(A/B) = (P(A \cap B))/(P(A))

In this problem, we have that:


P(A/B) is the probability that Ralph likes the movie, given that Melissa likes. The problem states that this is 10%. So
P(A/B) = 0.1


P(A) is the probability that Melissa likes the movie. The problem states that
P(A) = 0.37.

If they randomly select a movie from a video store, what is the probability that they both will like it?

This is
P(A \cap B).


P(A/B) = (P(A \cap B))/(P(A))


P(A \cap B) = P(A)*P(A/B)


P(A \cap B) = 0.37*0.10 = 0.037

There is a 3.7% probability that they both will like it.

User BHP
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