Question

NEED HELP ASAP !!!Six times the sum of two consecutive integers is eight more than five times the

larger integer. Find the integers.
The first integer is
The second integer is

Answer 1

The first integer is 1

The second integer is 2

Explanation:

Given that two numbers are consecutive:

Let the integers be:

First integer = x

Second Integer = x +1

Now according to given conditions the equation will be:

• Sum of two consecutive integers = x+ (x+1) = 2x +1
• Six times the sum of two consecutive integers =6(2x + 1) = 12x + 6
• Larger integer = x+1
• five times the larger integer = 5(x +1)= 5x + 5
• eight more than five times the larger integer= 5x +5 +8= 5x + 13

Final equation:

12x + 6 = 5x +13

Taking terms with x on left and others on right side

12x - 5x = 13 - 6 (signs of transferred terms will be changed)

7x = 7

Dividing both sides by 7 we get:

x = 1

So,

The first integer is 1

The second integer is 1+1 =2

I hope it will help you!