Question

It is given that one number is 6 more than another. If three times the sum of the two numbers is equal to 22 more than the larger number, what are the two numbers

Answer 1

First number=22

Second number=28

Explanation:

Since you don't know either of the numbers we can call the first number x. The second number is the first number plus 6 or x+6. The sum is 22 more than the larger number so x+6+22 or x+28. Using this we can create the equation x+x+6=x+28. In order to isolate x we would subract x from both sides ending up with x+6=28. Then subract 6 from both sides to get x=22. This means the first number equals 22. Then to solve for the second number you plug 22 in for x to get the equation 22+6= the second number, so the second number is equal to 28. Look below for just the equation.

x+x+6=x+6+22

2x+6=x+28

-x -x

x+6=28

-6. -6

x=22

22+6

=28

22+28= 28+22

50=50