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What are the slope, m, and y-intercept, (0, b), of the line described by

the equation 3x + 6y=12?
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I have no idea how to do this I need help

User ShortFuse
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1 Answer

5 votes

Answer:


\large \boxed{m = -(1)/(2);\text{ y-intercept = 2}}}

Explanation:

The slope-intercept form of an equation is

y = mx + b, where

m = the slope and

b = the y-intercept

We must solve your equation for y.

It will then be in the slope-intercept form.


\begin{array}{rcll}3x + 6y  & = & 12 & \\6y & = & 12 - 3x & \text{Subtracted 3x from each side}\\y&= &2 -(1)/(2)x& \text{Divided each side by 3}\\\mathbf{y} &= & \mathbf{-(1)/(2)x + 2}& \text{Rearranged terms}\\\end{array}\\\\\large \boxed{\mathbf{m = -(1)/(2);\textbf{y-intercept = 2}}}

The diagram below shows the equation of your graph with m = -½ and the y-intercept at (0, 2)

What are the slope, m, and y-intercept, (0, b), of the line described by the equation-example-1
User Bartvde
by
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