Question

If the detector readings are proportional to the amplitude of the microwave E field, the data from the first polarization experiment should be proportional to cos(θ) where θ is the angle between transmitter and detector. If the readings are proportional to the energy stored in the E field, the readings should be proportional to cos2(θ). Based on your data, are the detector readings proportional to amplitude, energy, or neither?

Answer 1

Fields and variables are proportional

Step-by-step explanation:

To solve the problem we must first identify the Vector Intensity,

The intensity is given by:

`I = I_ {0} cos^2 (\theta)`

We also know that the change given by the Intensity is always the square of the amplitude,

This is,

`I = A ^ 2`

The intensity is proportional to the change exerted on
`cos ^ 2 (\theta)`

That is to say that in turn the amplitus is proportional to the Intensity.

On the other hand, relating the two variables we have

`A ^ 2 = A ^ 2_ {0} cos ^ 2 \theta`

`A = A_ {0} cos \theta`

In this way we can conclude that the electric field of intensity is also proportional to
`cos ^ 2 \theta`