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A 10.00 mL sample of vinegar, an aqueous solution of acetic acid (HC₂H₃O₂), is titrated with 0.5062M NaOH, and 16.58 mL is required to reach the endpoint. If the density of the vinegar is 1.006 g/mL, what is the molarity of the acetic acid in the solution? You may assume that acetic acid contains one acidic hydrogen.

User Kenster
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1 Answer

3 votes

Answer:

0.8393 M

Step-by-step explanation:

Because acetic acid contains one acidic hydrogen, we can write the reaction as follows:

  • HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

Then we use the formula C₁*V₁=C₂*V₂, in order to calculate the concentration of acetid acid in vinegar:

  • C₁ * 10.00 mL = 0.5062 M * 16.58 mL
  • C₁ = 0.8393 M

And that's it, no calculation using density is required to solve this problem.

User Polo
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