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19 votes
19 votes
A cashier has a total of 136 bills, made up of fives and tens. The total value of the money

is $900. How many ten-dollar bills does the cashier have?

User Nirva
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1 Answer

14 votes
14 votes

Answer:

The number of ten-dollar bills is 44

Explanation:

we can transform this verbal problem into a system of equations:

Consider

F the number of fives and T the number of tens.

He has a total of 136 bills

means

F + T = 136

The total value of the money is $900

means

5F + 10T = 900

Now ,we got a system to solve:

F + T = 136

5F + 10T = 900

Let’s proceed by elimination:

F + T = 136

5F + 10T = 900

Then

5F + 5T = 5×136 = 680

5F + 10T = 900

Then

5F + 5T = 680 (Equation 1)

5F + 10T = 900 (Equation 2)

(2) - (1) ⇒ 5T = 900 - 680 = 220

⇒ 5T = 900 - 680 = 220

⇒ T = 220/5

⇒ T = 44

Since F = 136 - T then F = 136 - 44 = 92

User Fritza
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