Question

Write an equation in standard form that has a slip of 6 and passes through (-1,3)

Answer 1

6x - y = -9

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point on a line

We have

`m=6,\ (-1,\ 3)\to x_1=-1,\ y_1=3`

Substitute:

`y-3=6(x-(-1))`

`y-3=6(x+1)`

Convert to the standard form Ax + By = C:

`y-3=6(x+1)` use the distributive property a(b + c) = ab + ac

`y-3=6x+6` add 3 to both sides

`y=6x+9` subtract 6x from both sides

`-6x+y=9` change all signs

`6x-y=-9`