Question

10.0 g of fuel are burned under a calorimeter (container that measures energy flow) containing 200 g of water. The temperature of the water increases from 15.0oC to 55.0oC. Calculate the amount of heat released by the fuel per 1 gram of the fuel.

Answer 1

Answer : The amount of heat released by the fuel per 1 gram of the fuel is 3344 J.

Explanation :

Heat released by the fuel = Heat absorbed by the water

Formula used :

`Q=m* c* \Delta T`

or,

`Q=m* c* (T_2-T_1)`

where,

Q = heat absorbed = ?

m = mass of water = 200 g

c = specific heat of water =
`4.18J/g^oC`

`T_1` = initial temperature =
`15.0^oC`

`T_2` = final temperature =
`55.0^oC`

Now put all the given value in the above formula, we get:

`Q=200g* 4.18J/g^oC* (55.0-15.0)^oC`

`Q=33440J`

Thus, the heat absorbed by the water is 33440 J.

As, Heat released by the fuel = Heat absorbed by the water = 33440 J

Now we have to calculate the amount of heat released by the fuel per 1 gram of the fuel.

As, 10.0 grams of fuel released heat = 33440 J

So, 1 grams of fuel released heat =
`(33440)/(10.0)=3344J`

Hence, the amount of heat released by the fuel per 1 gram of the fuel is 3344 J.