Question

A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.

What is the pressure of air inside the balloon?


13 kPa

101 kPa

406 kPa

812 kPa

Answer 1

812 kPa

Step-by-step explanation:

• According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.

• Mathematically,
  `P\alpha (1)/(V)`

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

`P2=(P1V1)/(V2)`

Replacing the known variables with the values;

`P2=((101.5)(2.0L))/(0.25L)`

= 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa