Question

What is the equation on point slope form of a line that passes through the point -4, - 1 and 5, 7​

Answer 1

The equation of the line is c)
`( y+1) =  (8)/(9) ( x+4)`

Explanation:

Here, the two points are (x1, y1) = (-4,-1) and (x2, y2)= (5,7)

So, the slope of the line joining two points
`m = (y_2 - y_1)/(x_2 - x_1)`

Here,
`m = (7 - (-1))/(5 - (-4))  = (8)/(9)`

Also, by POINT SLOPE formula line equation is:

(y - y0) = m (x - x0) ; here m = slope and (x0, y0) is a point on line

So, here the equation of line is:

`(y - (-1)) = (8)/(9) ( x-(-4))\\or, ( y+1) =  (8)/(9) ( x+4)`

Hence,the equation of the line is c)
`( y+1) =  (8)/(9) ( x+4)`