Question

A basketball rolls off a deck that is 3.2 m from the pavement. The basketball lands 0.75 m from the edge of the deck. How fast was the basketball rolling? Seema lists the given values in a chart and determines that the unknown value is vx. Which describes Seema’s error? a) The y and x values are switched. b) The unknown is , not vx. c) The value for ay is not known. d) The value of y should be –3.2 m.

Answer 1

D The value of y should be –3.2 m.

Step-by-step explanation:

just got it right

Answer 2

d). The value of y should be -32m

Vx=0.92 m/s

Step-by-step explanation:

Using equation of motion uniform to y motion

`x_(f)=x_(o)+v_(o)*t+(1)/(2)*a*t^(2)\\x_(o)=0m\\v_(o)=0\\x_(f)=(1)/(2)*a*t^(2)\\x_(f)=-3.2m \\a=g=-9.8(m)/(s^(2)) \\`

So to find t that is the same time for all the motion

`t^(2)=(2*x_(f))/(a) \\t=\sqrt{(2*x_(f))/(a)}=\sqrt{(2*-3.2m)/(-9.8(m)/(s^(2)))}\\t=0.808s`

The value of Xf=-3.2m because the g is negative from the axis

Now in the axis 'x' to find Vx

`Vx=(0.75m)/(0.808S)\\ Vx=0.92 (m)/(s)`