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4 votes
Find three consecutive numbers such

that three times the first number is
equal to 9 more than the sum of the
other two.​

1 Answer

3 votes
3N = N + 1 + N + 2 + 9
N = 12

so 12, 13, 14??? Been awhile since I’ve done this so that could be incorrect very sorry if it is
User AsthaUndefined
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