Question

9. Write a balanced nuclear equation for the following: The isotope Strontium-90 decays by Q-

decay (1 point)
OfSr — He +56 kr
OS → H +39 kr
o Sr + Be +38kr
99 Sr → He +3 Se
SAST +7+99 Sr

Answer 1

Answer:
`_(38)^(90)\textrm{Sr}\rightarrow _(36)^(86)\textrm{Kr}+_2^4\textrm{He}`

Step-by-step explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

General representation of an element is given as:
`_Z^A\textrm{X}`

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

General representation of alpha decay :

`_Z^A\textrm{Sr}\rightarrow _(Z-2)^(A-4)Y+_2^4\alpha`

The balanced nuclear equation when the isotope Strontium-90 decays by Q- decay is :

`_(38)^(90)\textrm{Sr}\rightarrow _(36)^(86)\textrm{Kr}+_2^4\textrm{He}`