Question

Which​ of the following represents​ the equation of a line with the slope of 1/4 that passes through the point (-8,2)? chose all that apply

A. y-2=1/4(x+8)
B. y+2=1/4(x+8)
C. x-4y=-16
D. y=1/4x
E. y=4x+8

Answer 1

Answer: C x -4y = -16

Explanation:

Slope=∆y/∆x

M=y-y1/x-x1

M=1/4, y1 =2,x1=-8

1/4=y-2/x-(-8)

1/4=y-2/x+8

Cross multiply

4(y-2)=x+8

4y -8 = x + 8

-8-8= x - 4y

x +4y = -16 answer

Answer 2

Option A and Option C

The equation of a line with the slope of 1/4 that passes through the point (-8,2) is
`y-2=(1)/(4)(x+8)` or x - 4y = -16

Solution:

Given that the line passes through (-8, 2)

Slope is given as
`(1)/(4)`

Equation of line passing through point
`(x_1, y_1)` and having slope “m” is given as:

`\left(y-y_(1)\right)=m *\left(x-x_(1)\right)`

Plugging in the values
`x_1 = -8 ; y_1 = 2 ; m = (1)/(4)`

`\begin{array}{l}{y-2=(1)/(4)(x-(-8))} \\\\ {y-2=(1)/(4)(x+8)}\end{array}`

4y - 8 = x + 8

x - 4y = -16

Hence Option A and Option C is correct