Question

It takes 15 s to raise a 1200-kg car and the supporting 300-kg hydraulic car-lift platform to a height of 2.8 m. The velocity of the lift increases uniformly from zero to its maximum value at mid-height in 7.5 s and then decreases uniformly to zero in 7.5 s. Knowing that the peak power output of the hydraulic pump is 6 kW when the velocity is maximum, determine the maximum lift force provided by the pump.

Answer 1

Answer:14.774 kN

Step-by-step explanation:

Given

mass of car=1200 kg

mass of Hydraulic lift=300 kg

total time t=15 s

it covers s=1.4 in t=7.5 s

thus acceleration

`s=ut+(at^2)/(2)`

`2* 1.4=a* 7.5^2`

`a=0.0497 m/s^2`

`V_(max)=at=0.373 m/s`

Now Let F be the lift Force

F-mg=ma

F=m(g+a)

`F=1500* (9.8+0.0497)=14,774.55 N`