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What is the molarity of 125 ml of solution containing 5.31 g sodium nitrate​

1 Answer

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Answer:

0.5 moles/L or 0.5 M

Step-by-step explanation:

  • Molarity is the concentration of a solution in moles per liter.
  • It is calculated by;

Molarity = Number of moles ÷ Volume

In this case;

Volume = 125 mL

Mass of sodium nitrate = 5.31 g

We are required to calculate the molarity of sodium nitrate

Step 1: Calculate the number of moles of sodium nitrate

Moles = Mass ÷ Molar mass

Molar mass of sodium nitrate = 84.9947 g/mol

Therefore,

Moles of NaNO₃ = 5.31 g ÷ 84.9947 g/mol

= 0.0625 moles

Step 2: Molarity of sodium nitrate

Remember;

Molarity = Moles ÷ Volume

Volume of NaNO₃ = 0.125 L

Therefore;

Molarity = 0.0625 moles ÷ 0.125 L

= 0.5 Moles/L or 0.5 M

Thus; the concentration of sodium nitrate is 0.5M

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