Answer: Our required probability is 0.0002.
Explanation:
Since we have given that
Probability that the professors are excellent = 20% = 0.20
Probability that the professors are good = 50% = 0.50
Probability that the professors are fair = 20% = 0.20
Probability that the professors are bad = 10% = 0.10
Number of professors = 12
We need to find the probability that 4 are excellent and 3 are good.
So, it becomes,
![P(\text{4 are excellent and 3 are good})=(0.2)^4* (0.5)^3=0.0002](https://img.qammunity.org/2020/formulas/mathematics/college/2lqer13ki53t2thrzqw50v26kutj2j1vxx.png)
Hence, our required probability is 0.0002.