Question

The length of a rectangle is five times it’s width if the area of the rectangle is 320m^2 find its perimeter

Answer 1

Perimeter of the rectangle = 96 meters.

Explanation:

Let the width of the rectangle = K

So, the length of the rectangle = 5K

Area = 320 sq meters

Now, Area of a Rectangle = Length x Width

⇒ 320 = K x 5K

or,
`5K^(2) = 320\\or, K^(2)  = (320)/(5)   = 64`

So, the vlue of K = 8 or, K = -8

But as K represents a length hence, K ≠ -8

So, the width of the rectangle = 8 meters

and the length of the rectangle = 8 x 5 = 40 meters

Now, Perimeter = 2(length + width)

= 2(8 + 40) = 96 meters.

So, the perimeter of the rectangle = 96 meters.