Answer:
![6.0\cdot 10^(14) Hz](https://img.qammunity.org/2020/formulas/physics/middle-school/ac8oqcc2xxwznzxzm2akvn3sz4etbnjc64.png)
Step-by-step explanation:
The frequency and the wavelength of an electromagnetic wave are related by the wave equation:
![c=f \lambda](https://img.qammunity.org/2020/formulas/physics/high-school/pujf2slcux6tuz1i64aby6yqgsc32v3r6t.png)
where
is the speed of light
f is the frequency
is the wavelength
For the light wave in this problem,
is the wavelength
So, solving the equation for f, we find its frequency:
![f=(c)/(\lambda)=(3.0\cdot 10^8)/(5.0\cdot 10^(-7))=6.0\cdot 10^(14) Hz](https://img.qammunity.org/2020/formulas/physics/middle-school/dgn5q60f9ome7hl70ocebqv7zoo5eillao.png)