Question

what volume of concentrated HCl (12 M) is needed to fully neutralize 5 mL of a 1 M solution of sodium bicarbonate (show your setup and your work). Also write the balanced chemical equation for this neutralization reaction.

Answer 1

0.417M

Step-by-step explanation:

Equation of the reaction

2HCl+Na2CO3→2NaCl+H2O+CO2

From dilution principle

no of mole=conc × volume

from the balanced equation

no of mole of Na2CO3=2× no of mole of HCl

HCl=acid=A

Na2CO3=base=B

since n=cv

Conc of base × vol of base=2× conc of acid×volume of acid

2M×5ml=2×12M×Volume of acid

volume of acid=10/24

=0.417(3 decimal place)